How's ur Maths??
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How Your Maths?
Three Friends, A, B & C went to a restaurant. After dinner they asked for bill, the amount of bill was $30 /- They decided to pay the bill amount on equal share.
Everybody took out $10 /- from their pocket and paid the bill.
The waiter realized that the amount of their bill was $25 /- and not $30 /- He took $ 5 /- from counter and decided to return them. Then he thought there are 3 how will they share $5 /- ?
So he has decided to keep $2 /- to him and return only $3 /- to them.
He came to their table and returned them $3 /- with apology.
Everybody took $1 /- and put in their pockets.
Now the question is first time everyone paid $10 /-
later they get $1 /- refunded. So everybody paid $9 /-
$9 x 3 = $27 /-
The waiter put $2 /- in his pocket.
$27 + $2 = 29
So...... Where is the remaining $1 /- ??? -
This one i hear until sian liao, the thing is the bill was $25 and they paid $27 so they overpaid by $2 which is in the waiter's pocket.
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but they paid 30 leh... how come after adding all up only 29??Originally posted by The man who was death:This one i hear until sian liao, the thing is the bill was $25 and they paid $27 so they overpaid by $2 which is in the waiter's pocket. -
I only now how to look at it my wayOriginally posted by carpe diem jur:but they paid 30 leh... how come after adding all up only 29??
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There's no $1...becoz it's Maths calculation.Originally posted by carpe diem jur:How Your Maths?
Three Friends, A, B & C went to a restaurant. After dinner they asked for bill, the amount of bill was $30 /- They decided to pay the bill amount on equal share.
Everybody took out $10 /- from their pocket and paid the bill.
The waiter realized that the amount of their bill was $25 /- and not $30 /- He took $ 5 /- from counter and decided to return them. Then he thought there are 3 how will they share $5 /- ?
So he has decided to keep $2 /- to him and return only $3 /- to them.
He came to their table and returned them $3 /- with apology.
Everybody took $1 /- and put in their pockets.
Now the question is first time everyone paid $10 /-
later they get $1 /- refunded. So everybody paid $9 /-
$9 x 3 = $27 /-
The waiter put $2 /- in his pocket.
$27 + $2 = 29
So...... Where is the remaining $1 /- ???
If from the arrangement of calculation made above:
1] $30 >> Initial Bill
2] $25 >>Actual bill
3] $(5-2) = $3 >> $2 Waiter"s keep
4] $3/3 = $1 >>Refund divided by 3 guys
5] $(10-1) = $9 >> Actual payout by each guy.
6] $9 * 3 = $27 >> Total payout by 3 guys.
7] $(27+2) = $29 >> Correct calculation.
Therefore, there's no missing $1 or $30 exist becoz ACTUALLY the 3 guys paid onli $9.
---> $9 *3 = $27
---> $(27-2) $25 [Total Bill] ; $2 is Waiter's keep.